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Aptitude Solved Problems
1. Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs 4000, the new ratio becomes 40 : 57. What is Sumit present salary.
Answer: Rs. 38000
Explanation:
Let the original Salaries of Ravi and Sumit is 2x and 3x.
( 2 x + 4000 ) / ( 3 x + 4000 ) = ( 40 / 57 )
57 ( 2x + 4000 ) = 40 ( 3x + 4000)
( 114 x + 228000 ) = ( 120 x + 160000 )
( 228000 - 160000 ) = ( 120 x - 114 x )
6 x = 68000
3 x = 34000
Sumit Salary = ( 3x + 4000 )
= ( 34000 + 4000 )
= 38000
∴ Sumit present salary is Rs. 38000
2. The telephone bill of a certain establishment is party fixed and partly varies as the number of calls consumed. In a certain month 540 units are consumed and the bill is Rs.1800. In another month 620 units are consumed then the bill becomes Rs.2040. In another month 500 units are consumed due to more holidays. The bill for that month would be?
Answer: Rs. 1680
Explanation:
Let the fixed amount be Rs. x and the cost of each unit be Rs. y
Then, ( 540y + x ) = 1800 ... ( eqn 1 )
And ( 620y + x ) = 2040 ... ( eqn 2 )
On subtracting (1) from (2),
80 y = 240
⇒ y = 3
Putting y = 3 in (1)
( 540 * 3 ) + x = 1800
x = ( 1800 - 1620 )
x = 180
Fixed charges = Rs. 180
Charge per unit = Rs. 3
Total charges for consuming 500 units
= 180 + ( 500 * 3 )
= Rs.1680
∴ The bill for that month is Rs. 1680
3. Find the area of a square, one of whose diagonal is 6 m long.
Answer: 18 m2
Explanation:
Diagonal = 6 m
Area of the square = ( 1 / 2 ) * ( Diagonal )2
= [ ( 1 / 2 ) * 6 * 6 ] m2
= 3 * 6 m2
= 18 m2
∴ Area of the square is 18 m2.
challenge your brain in aptitude!!
1. Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs 4000, the new ratio becomes 40 : 57. What is Sumit present salary.
Answer: Rs. 38000
Explanation:
Let the original Salaries of Ravi and Sumit is 2x and 3x.
( 2 x + 4000 ) / ( 3 x + 4000 ) = ( 40 / 57 )
57 ( 2x + 4000 ) = 40 ( 3x + 4000)
( 114 x + 228000 ) = ( 120 x + 160000 )
( 228000 - 160000 ) = ( 120 x - 114 x )
6 x = 68000
3 x = 34000
Sumit Salary = ( 3x + 4000 )
= ( 34000 + 4000 )
= 38000
∴ Sumit present salary is Rs. 38000
2. The telephone bill of a certain establishment is party fixed and partly varies as the number of calls consumed. In a certain month 540 units are consumed and the bill is Rs.1800. In another month 620 units are consumed then the bill becomes Rs.2040. In another month 500 units are consumed due to more holidays. The bill for that month would be?
Answer: Rs. 1680
Explanation:
Let the fixed amount be Rs. x and the cost of each unit be Rs. y
Then, ( 540y + x ) = 1800 ... ( eqn 1 )
And ( 620y + x ) = 2040 ... ( eqn 2 )
On subtracting (1) from (2),
80 y = 240
⇒ y = 3
Putting y = 3 in (1)
( 540 * 3 ) + x = 1800
x = ( 1800 - 1620 )
x = 180
Fixed charges = Rs. 180
Charge per unit = Rs. 3
Total charges for consuming 500 units
= 180 + ( 500 * 3 )
= Rs.1680
∴ The bill for that month is Rs. 1680
3. Find the area of a square, one of whose diagonal is 6 m long.
Answer: 18 m2
Explanation:
Diagonal = 6 m
Area of the square = ( 1 / 2 ) * ( Diagonal )2
= [ ( 1 / 2 ) * 6 * 6 ] m2
= 3 * 6 m2
= 18 m2
∴ Area of the square is 18 m2.
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